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59=0.5(x^2-3)
We move all terms to the left:
59-(0.5(x^2-3))=0
We calculate terms in parentheses: -(0.5(x^2-3)), so:We get rid of parentheses
0.5(x^2-3)
We multiply parentheses
0.5x^2-1.5
Back to the equation:
-(0.5x^2-1.5)
-0.5x^2+1.5+59=0
We add all the numbers together, and all the variables
-0.5x^2+60.5=0
a = -0.5; b = 0; c = +60.5;
Δ = b2-4ac
Δ = 02-4·(-0.5)·60.5
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-11}{2*-0.5}=\frac{-11}{-1} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+11}{2*-0.5}=\frac{11}{-1} =-11 $
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